AskiitianExpert Pramod-IIT-R
Last Activity: 15 Years ago
Dear student Ms. Shefali,
by the objective approach; let the cross section area is A0 and common temp T0, common pressure P0,
for gas 1: PV=nRT
P0 * A0 * L1 = [w/32] R * T0 ...............(1)
for gas 2: P0 * A0 * L2 = [w/28] * R * T0..............(2)
where L indicates the length of the arc on ring
By equation 1 / 2
L1/L2 = 28/32 = 7/8
So angle made by gas (1) = 7/[7+8] * 360
= 7/15*360 = 168 degree
Please feel free to post as many doubts on our discussion forum as you can.
If you find any question Difficult to understand - post it here and we will get you the answer and detailed
solution very quickly.
We are all IITians and here to help you in your IIT JEE & AIEEE preparation.
All the best.
Regards,
Askiitians Experts
Pramod Kumar
IITR Alumni