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An ideal carnot engine, whose efficiency is 40% receives heat at 500 K. If its efficiency is 50%, then the intake temperature for the same exhaust temperature is

(a) 600 K

(b) 700 K

(c) 800 K

(d) 900 K

Aditi Chauhan , 11 Years ago
Grade 10
anser 2 Answers
Simran Bhatia

Last Activity: 11 Years ago

(a)

Efficiency of carnot engine (h1) = 40%

= 0.4; Initial intake temperature (T1) = 500 K

and new efficiency (h2) = 50% = 0.5.

Kushagra Madhukar

Last Activity: 4 Years ago

Dear student,
Please find the answer to your question.
 
Efficiency of carnot engine (n1) = 40% = 0.4;
Initial intake temperature (T1) = 500 K
and new efficiency (n2) = 50% = 0.5
Now, Efficiency, n = 1 – T2/T1
or, T2/T1 = 1 – n
In first case, T2/500 = 1 – 0.4 = 0.6
=> T2 = 0.6 x 500 = 300 K
In second case, 300/T1 = 1 – 0.5 = 0.5
=> T1 = 300/0.5 = 600 K
 
Thanks and regards,
Kushagra

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