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110 joules of heat is added to a gaseous system, whose internal energy is 40j; then the amount of external work done is
(a) 150 J
(b) 70 J
(c) 110 J
(d) 40 J
(b)
DQ = DU + DW
Þ DW = DQ - DU = 110 - 40 = 70 J
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