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A thermodynamic process is shown in the figure.
The pressures and volumes corresponding to some points in the figure are
PA = 3 × 104 Pa
VA = 2 × 10-3 m3
PB = 8 × 104 Pa
VD = 5 × 10-3m3.
In process AB, 600 J of heat is added to the system and in process BC, 200 J of heat is added to the system. The change in internal energy of the system in process AC would be
(a) 560 J
(b) 800 J
(c) 600 J
(d) 640 J
(a)
Since AB is an isochoric process, so, no work is done. BC is isobaric process,
\ W = PB × (VD - VA) = 240 J
Therefore, DQ = 600 + 200 = 800 J
Using DQ = DU + DW
Þ DU = DQ - DW = 800-240 = 560 J
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