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A thermodynamic process is shown in the figure.The pressures and volumes corresponding to some points in the figure arePA = 3 × 104 PaVA = 2 × 10-3 m3PB = 8 × 104 PaVD = 5 × 10-3m3.In process AB, 600 J of heat is added to the system and in process BC, 200 J of heat is added to the system. The change in internal energy of the system in process AC would be(a) 560 J(b) 800 J(c) 600 J(d) 640 J

Simran Bhatia , 11 Years ago
Grade 11
anser 2 Answers
Amit Saxena

Last Activity: 11 Years ago

(a)

Since AB is an isochoric process, so, no work is done. BC is isobaric process,

\ W = PB × (VD - VA) = 240 J

Therefore, DQ = 600 + 200 = 800 J

Using DQ = DU + DW

Þ DU = DQ - DW = 800-240 = 560 J

9686565835

Last Activity: 3 Years ago

Since ab is an isochoric process -volume constant 
Bc is isobaric process -pressure constant 
DeltaQ =600j+200j
Work is 240j
DeltaQ=deltaU+ work
Work=800-240
560j
 

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