A thermodynamic process is shown in the figure.The pressures and volumes corresponding to some points in the figure arePA = 3 × 104 PaVA = 2 × 10-3 m3PB = 8 × 104 PaVD = 5 × 10-3m3.In process AB, 600 J of heat is added to the system and in process BC, 200 J of heat is added to the system. The change in internal energy of the system in process AC would be(a) 560 J(b) 800 J(c) 600 J(d) 640 J
Simran Bhatia , 11 Years ago
Grade 11
2 Answers
Amit Saxena
Last Activity: 11 Years ago
(a)
Since AB is an isochoric process, so, no work is done. BC is isobaric process,
\ W = PB × (VD - VA) = 240 J
Therefore, DQ = 600 + 200 = 800 J
Using DQ = DU + DW
Þ DU = DQ - DW = 800-240 = 560 J
9686565835
Last Activity: 3 Years ago
Since ab is an isochoric process -volume constant
Bc is isobaric process -pressure constant
DeltaQ =600j+200j
Work is 240j
DeltaQ=deltaU+ work
Work=800-240
560j
Provide a better Answer & Earn Cool Goodies
Enter text here...
LIVE ONLINE CLASSES
Prepraring for the competition made easy just by live online class.
Full Live Access
Study Material
Live Doubts Solving
Daily Class Assignments
Ask a Doubt
Get your questions answered by the expert for free