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A thermodynamic process is shown in the figure. The pressures and volumes corresponding to some points in the figure are P A = 3 × 10 4 Pa V A = 2 × 10 -3 m 3 P B = 8 × 10 4 Pa V D = 5 × 10 -3 m 3 . In process AB, 600 J of heat is added to the system and in process BC, 200 J of heat is added to the system. The change in internal energy of the system in process AC would be (a) 560 J (b) 800 J (c) 600 J (d) 640 J



A thermodynamic process is shown in the figure.


The pressures and volumes corresponding to some points in the figure are



PA = 3 × 104 Pa 


VA = 2 × 10-3 m3


PB = 8 × 104 Pa


VD = 5 × 10-3m3.


 


In process AB, 600 J of heat is added to the system and in process BC, 200 J of heat is added to the system. The change in internal energy of the system in process AC would be   


        (a)    560 J


        (b)    800 J


        (c)    600 J


        (d)    640 J


Grade:11

2 Answers

Amit Saxena
35 Points
7 years ago

(a)

Since AB is an isochoric process, so, no work is done. BC is isobaric process,

\ W = PB × (VD - VA) = 240 J

Therefore, DQ = 600 + 200 = 800 J

Using DQ = DU + DW

Þ DU = DQ - DW = 800-240 = 560 J

9686565835
15 Points
6 months ago
Since ab is an isochoric process -volume constant 
Bc is isobaric process -pressure constant 
DeltaQ =600j+200j
Work is 240j
DeltaQ=deltaU+ work
Work=800-240
560j
 

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