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2 moles of a diatomic gas undergoes the process PT^2/V = constant. Then the molar heat capacity of the gas during the process is ??

2 moles of a diatomic gas undergoes the process PT^2/V = constant. Then the molar heat capacity of the gas during the process is ??

Grade:12

1 Answers

Amar Kumar
27 Points
7 years ago

For diatomic gases,

No of degree 0f freedom = 5        when no vibration

so ,  Cv = 5/2 R

       Cp =  7/2 R 

 

Thanks & Regards

Amar Kumar

AskIITians Faculty

M.Tech, IIT Delhi

 

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