Grade 12th PassThermal Physics

find the amount of work done to increase the temperature of one mole ideal gas by 30 degree if it is expanding under the condition V directly proportional to T^3/2

vishal srivastava

13 Years agoGrade 12th Pass

3 Answers

Vikas TU

13 Years ago

Under the condition V directly proportional to T^3/2

we get, TV^-2/3 = k^2/3 (constant)

Relating from the eqn. TV^Y-1= K₀ (CONSTANT)

Y - 1 = - 2/3

Y = 1 - 2/3

Y = 1/3 [: - Y = C_v/C_p]

Now, W = (nRT)/(1-Y)

pUTTING ALL THE VALUES = 1.R.30/(1 - 1/3)

= (30R)/(2/3)

=45R

=375 J.

Plz Approve

plz approve

Arnav singh

7 Years ago

V proportional to T^2/3 , so

VT^-2/3= C(constant)

TV^-3/2=C'(some other constant)

Now as TV^Y-1 =C ,therefore

Y-1= -3/2

Y=-1/2

Now , W= nR∆T/1-Y => 1.8.314.30/ 1+1/2

=>1.8.314.30.2/3=> 166.28 J

Rishi Sharma

6 Years ago

Dear Student,
Please find below the solution to your problem.

V proportional to T^2/3 , so
VT^-2/3= C(constant)
TV^-3/2=C'(some other constant)
Now as TV^Y-1 =C ,therefore
Y-1= -3/2
Y=-1/2
Now , W= nR∆T/1-Y => 1.8.314.30/ 1+1/2
=>1.8.314.30.2/3=> 166.28 J

Thanks and Regards