find the amount of work done to increase the temperature of one mole ideal gas by 30 degree if it is expanding under the condition V directly proportional to T^3/2
vishal srivastava , 11 Years ago
Grade 12th Pass
3 Answers
Vikas TU
Last Activity: 11 Years ago
Under the condition V directly proportional to T^3/2
we get, TV-2/3 = k2/3 (constant)
Relating from the eqn. TVY-1 = K0 (CONSTANT)
Y - 1 = - 2/3
Y = 1 - 2/3
Y = 1/3 [: - Y = Cv/Cp]
Now, W = (nRT)/(1-Y)
pUTTING ALL THE VALUES = 1.R.30/(1 - 1/3)
= (30R)/(2/3)
=45R
=375 J.
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Arnav singh
Last Activity: 6 Years ago
V proportional to T^2/3 , so
VT^-2/3= C(constant)
TV^-3/2=C'(some other constant)
Now as TV^Y-1 =C ,therefore
Y-1= -3/2
Y=-1/2
Now , W= nR∆T/1-Y => 1.8.314.30/ 1+1/2
=>1.8.314.30.2/3=> 166.28 J
Rishi Sharma
Last Activity: 4 Years ago
Dear Student, Please find below the solution to your problem.
V proportional to T^2/3 , so VT^-2/3= C(constant) TV^-3/2=C'(some other constant) Now as TV^Y-1 =C ,therefore Y-1= -3/2 Y=-1/2 Now , W= nR∆T/1-Y => 1.8.314.30/ 1+1/2 =>1.8.314.30.2/3=> 166.28 J
Thanks and Regards
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