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Dear Rajveer,Apply Grahams law of effusion.it is:- rate(r) of effusion/diffusion is proportional to 1/ root [density(d) ]hecne r1/r2 = root( d2/d1 ) => r1/r2 = root ( M2/M1 ) since [2. vapour density(d)=molecular mass(M) ] now put rate=Volume/time=V/t all sums of this type are solved by this concept.Hope it gets cleared now.Regards.
r=(volume of gas)/time taken.
rate of effusion=r=(volume of nitrogen gas effusing from the cylinder)/(time taken)
also since pressure and temperature are constant, volume is proprtional to no. of moles
so,r=(no. of moles of N2 effusing)/(time taken)
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