Flag Thermal Physics> piston-spring-expansion...
question mark

A cylinder is fitted with a frictionless piston is connected to a spring which exerts force proportional to the displacement from its equilibrium position. Initially the gas inside is at 200kPa and the volume is 0.21 cubic metre. The gas is heated until the volume is doubled and pressure became 500 kPa. Find the total work done by the gas in the process. Take atmospheric pressure as 100kPa.

Kirti Sharma , 13 Years ago
Grade 11
anser 1 Answers
Askiitians Tutor Team

To find the total work done by the gas during the heating process, we can use the concept of work done in a thermodynamic system. In this case, the gas expands against both the spring and the atmospheric pressure. The work done by the gas can be calculated using the formula for work in a quasi-static process, which involves integrating the pressure with respect to volume. Let's break this down step by step.

Understanding the System

We have a cylinder with a frictionless piston, and the gas inside is initially at a pressure of 200 kPa and a volume of 0.21 m³. When the gas is heated, its volume doubles to 0.42 m³, and the pressure increases to 500 kPa. The atmospheric pressure is given as 100 kPa.

Work Done by the Gas

The total work done by the gas during the expansion can be calculated using the formula:

  • W = ∫ P dV

In this case, we need to consider the work done against both the atmospheric pressure and the spring force. The effective pressure that the gas works against during the expansion can be expressed as:

  • P_eff = P_gas - P_atm

Calculating Work Done

Initially, the gas is at 200 kPa and expands to 500 kPa. However, we need to consider the work done in two segments: from the initial state to the final state. The work done can be calculated as follows:

1. Work Done Against Atmospheric Pressure

The work done against atmospheric pressure can be calculated using the formula:

  • W_atm = (P_final - P_atm) * (V_final - V_initial)

Substituting the values:

  • P_final = 500 kPa
  • P_atm = 100 kPa
  • V_final = 0.42 m³
  • V_initial = 0.21 m³

Thus, the work done against atmospheric pressure is:

  • W_atm = (500 kPa - 100 kPa) * (0.42 m³ - 0.21 m³)
  • W_atm = 400 kPa * 0.21 m³ = 84 kJ

2. Work Done Against the Spring

To find the work done against the spring, we need to know the spring constant and how the force varies with displacement. Since the problem states that the spring exerts a force proportional to the displacement, we can assume a linear relationship. However, without specific values for the spring constant or the displacement, we can only estimate this part. For simplicity, let's assume the work done against the spring is negligible compared to the work done against atmospheric pressure.

Total Work Done

Since we have calculated the work done against atmospheric pressure and assumed the work done against the spring is negligible, the total work done by the gas during the process can be approximated as:

  • Total Work Done (W_total) ≈ W_atm = 84 kJ

Therefore, the total work done by the gas in the process is approximately 84 kJ. This calculation highlights the importance of understanding the forces acting on the gas during expansion and how they contribute to the overall work done in a thermodynamic process.

ApprovedApproved
Last Activity: 9 Months ago
star
LIVE ONLINE CLASSES

Prepraring for the competition made easy just by live online class.

tv

Full Live Access

material

Study Material

removal

Live Doubts Solving

assignment

Daily Class Assignments