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A vessel contains 1 mole of O2 and 1 mole of He. The value of γ(gamma) for the mixture is?
HOW? Pleassee explain
Thank u JAYANT for the formula. It helped me a lot. But the answer I got is 1.5.
But once again THANKS A LOT
LET
n1= no. moles of oxygen.=1 mole
n2=no. of moles of helium = 1 moles
Q is the total heat of mixture, Q1 is heat of pure oxygen, Q2 is heat of pure he mixture.
hence by conservation of energy,
Q = Q1 + Q2
(n1+ n2)Cp.dt = n1Cp1.dt + n2Cp2.dt
2.Cp = Cp1 + Cp2
=7/2 R + 5/2R
= 6R
Cp = 3R
Cv= 3R-R=2R
gamma= 3/2=1.5
Use the formula:
{N(oxygen)+N(helium)}/{γ(mixture)-1}=N(oxygen)/{γ(oxygen)-1}+N(helium)/{γ(helium)-1}
where,
N(oxygen) and N(helium) are given
and,
γ(oxygen)=gamma of diatomic gas(7/2)
γ(helium)=gamma of monoatomic gas(5/3)
ans=3/2
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