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A bullet is fired normallyon a wodden plank,which is immovable.it losses 25% of it's momebtum in penetrating a thickness of 3.5cm.the total thickness penetrated by bullet is-
Mass is constant. So, 25% loss in momentum => 25% loss in velocity
Initial velocity u becomes 3u/4
2aS=v2-u2
S = 3.5cm, u=u, v=3u/4
7a = (9u2/16) - u2
i.e 7a = -7u2/16 or a = -u2/16
After coming to rest, v = 0 , u = u , a = -u2/16
2aD = 0 - u2
2(-u2/16)D = -u2
i.e. D = 8 cm
energy hisab kitab 1/16 of energy works=3.5cm 9/16 of energy will work for 9*3.5=31.5cm net distance=31.5+3.5=35cm
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