sir, My question is:- why not we consider change of pressure of gas to calculate work done? while equation of work done is #W = P#V +V#P

A container filled with a sample of an Idea gas at the pressure of 1.5atm. the gas is compressed isothermal ly to one fourth of its original volume. What is the new pressure of the gas?

 

how do we know the electric field due to an electric dipole of dipole moment P at distance r from the centre of dipole is fiven by .. where theta is angle between p amd r vector..

A A mole of helium gas initially at stp undergoes an isovolumetric process in which its pressure falls to half its initial value. The work done by gas is

Please help me with the  answer of this question  related to radiation graph