An object is at temp of 400 degree celcius.At what temp would it radiate energy twice as fast?The temp of the surroundings may be as sumed to be negligible

Question

AskIITians Expert Hari Shankar IITD · Answer

By STefan-Boltzmann law, Rate of heat radiation E is proportional to T⁴ .

Let E = kT⁴.

Also, let the iniotial energy radiated be E₁.

Temperature T = 400 C = 400+273 K = 673 K

So, E₁= k (673)⁴ .................(1)

Let rate of heat radiation be 2E₁ at temperature T₂.

Then, 2E₁ = k(T₂)⁴

2E₁ = [E₁/(673)⁴] (T₂)⁴ using (1)

(T₂)⁴ = 2 (673)⁴

T₂ = (2)^1/4 * 673 = 1.19 * 673 = 800.33 K

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An object is at temp of 400 degree celcius.At what temp would it radiate energy twice as fast?The temp of the surroundings may be as sumed to be negligible

An object is at temp of 400 degree celcius.At what temp would it radiate energy twice as fast?The temp of the surroundings may be as sumed to be negligible

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