Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
2 blocks of masses 10 kg and 20 kg moving at speeds of 10m/sec and 20m/sec resp. in oppsite directions collide.If the collision is completly inelastic,find the thermal energy developed in the process.
Dear Allina,
Ans;- The final velocity of the combination is v (let) towards the initial direction of the 20 kg body Hence the Eq of the conservation of momentum is
(20*20)-(10*10)= 30v
Hence v=10m/s
From the conservation of the total energy we get,
1/2(20*20²+10*10²)=H+1/2(30*10²)
Solving we get H=2000 J
=2 kJ
Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE preparation.
All the best Alina!!!
Regards,
Askiitians Experts SOUMYAJIT IIT_KHARAGPUR
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !