12 mole of helium is contained in a container at S.T.P. How much heatenergy is needed to double the pressure of the gas, keeping the volumeconstant? Heat capacity of gas is 3 J g–1 K–1.

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Arun · Answer

n = &frac12; Cv = 3J/gm-K M = 4 Cv = MCv = 12 J/gm-K M = molecular mass P2/P1 = T2/T1 = 2 Delta T = T2- T1 = 273 K Delta Q = n Cv (Delta T) On solving Delta Q = 1638 J Regards Arun (askIITians forum expert)

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12 mole of helium is contained in a container at S.T.P. How much heatenergy is needed to double the pressure of the gas, keeping the volumeconstant? Heat capacity of gas is 3 J g–1 K–1.

12 mole of helium is contained in a container at S.T.P. How much heatenergy is needed to double the pressure of the gas, keeping the volumeconstant? Heat capacity of gas is 3 J g–1 K–1.

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12 mole of helium is contained in a container at S.T.P. How much heatenergy is needed to double the pressure of the gas, keeping the volumeconstant? Heat capacity of gas is 3 J g–1 K–1.

12 mole of helium is contained in a container at S.T.P. How much heatenergy is needed to double the pressure of the gas, keeping the volumeconstant? Heat capacity of gas is 3 J g–1 K–1.

1 Answers

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