100g of ice at 0 degree Celsius is mixed with 10g of steam at 100 degree Celsius. Find the final composition

Latent heat of ice =m×l 100×80=8000Latent heat of steam =m×l =10×540 L.H of ice is greater than steam Specific heat of steam = mct =10×1×100=10005400+1000=6400 for steamCompositionQ=mlm=q/lm=6400/80m=80100-80=20g of ice 10+80=90g water

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