Grade 9Thermal Physics

100g of ice at 0 degree Celsius is mixed with 10g of steam at 100 degree Celsius. Find the final composition

Samyak

6 Years agoGrade 9

2 Answers

Arun

6 Years ago

Latent heat of ice =m×l 100×80=8000Latent heat of steam =m×l =10×540 L.H of ice is greater than steam Specific heat of steam = mct =10×1×100=10005400+1000=6400 for steamCompositionQ=mlm=q/lm=6400/80m=80100-80=20g of ice 10+80=90g water

Vikas TU

6 Years ago

Dear student

Kindly follow the below link to get ans of your question.

https://www.askiitians.com/forums/Thermal-Physics/100g-ice-at-0-o-c-is-mixed-with-10g-steam-at-100-o_186731.htm

Hope this helps

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100g of ice at 0 degree Celsius is mixed with 10g of steam at 100 degree Celsius. Find the final composition

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2 Answers

Arun

Vikas TU

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