100g of ice at 0°C is mixed with 100g of water at 100°C what will be the final temperature of mixture

Question

Eshan · Answer

Dear student,

Amount of heat required in melting 100g of ice= $mL_f=100\times 80cal=8kcal$

Let the final temperature of water be $T$ .

From conservation of energy,

Heat required to melt the ice+Heat required to raise the temperature of melted ice to ‘T’=Heat given out by cooling to water at $100^{\circ}C$ to ‘T’

$\implies 8kcal+0.1(1)(T-0)=0.1(1)(100-T)$
$\implies T=10^{\circ}C$

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100g of ice at 0°C is mixed with 100g of water at 100°C what will be the final temperature of mixture

100g of ice at 0°C is mixed with 100g of water at 100°C what will be the final temperature of mixture

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100g of ice at 0°C is mixed with 100g of water at 100°C what will be the final temperature of mixture

100g of ice at 0°C is mixed with 100g of water at 100°C what will be the final temperature of mixture

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