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1 litre of gas at STP is expanded adibatically to 3 litre.Find work done by gas. gaama=1.4&3power1.4=4.65
V1=1l⇒ initial volume, V1=1×10−3m3V2=3l⇒ final volume, V2=3×10−3m3At STP:T=273KP1=101.325kPa⇒ initial pressure Y=1.4Work done in adiabatic process, ΔW=−(Y−1P2V2−P1V1)adiabatic ⇒PVγ=constant⇒P1V1γ=P2V2γ⇒P2=P1(V2V1)γ=1.01325(3×10−31×10−3)1.4 ⇒P2=101.325×(3)1.41=(4.6555101.325)kPa P2=21.7646KPa ΔW=−(1.4−121.7646×103×3×10−3−101.325×103×1×10−3) ΔW=−(0.465.2937−101.325)=90.5JConsidering only magnitude, the work done by the air will be 90.5J
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