1 litre of gas at STP is expanded adibatically to 3 litre.Find work done by gas. gaama=1.4&3power1.4=4.65

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Arun · Answer

V 1 ​ = 1 l ⇒ initial volume, V 1 ​ = 1 × 1 0 − 3 m 3 V 2 ​ = 3 l ⇒ final volume, V 2 ​ = 3 × 1 0 − 3 m 3 At STP: T = 2 7 3 K P 1 ​ = 1 0 1 . 3 2 5 k P a ⇒ initial pressure Y = 1 . 4 Work done in adiabatic process, Δ W = − ( Y − 1 P 2 ​ V 2 ​ − P 1 ​ V 1 ​ ​ ) adiabatic ⇒ P V γ = c o n s t a n t ⇒ P 1 ​ V 1 γ ​ = P 2 ​ V 2 γ ​ ⇒ P 2 ​ = P 1 ​ ( V 2 ​ V 1 ​ ​ ) γ = 1 . 0 1 3 2 5 ( 3 × 1 0 − 3 1 × 1 0 − 3 ​ ) 1 . 4 ⇒ P 2 ​ = 1 0 1 . 3 2 5 × ( 3 ) 1 . 4 1 ​ = ( 4 . 6 5 5 5 1 0 1 . 3 2 5 ​ ) k P a P 2 ​ = 2 1 . 7 6 4 6 K P a Δ W = − ( 1 . 4 − 1 2 1 . 7 6 4 6 × 1 0 3 × 3 × 1 0 − 3 − 1 0 1 . 3 2 5 × 1 0 3 × 1 × 1 0 − 3 ​ ) Δ W = − ( 0 . 4 6 5 . 2 9 3 7 − 1 0 1 . 3 2 5 ​ ) = 9 0 . 5 J Considering only magnitude, the work done by the air will be 9 0 . 5 J

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1 litre of gas at STP is expanded adibatically to 3 litre.Find work done by gas. gaama=1.4&3power1.4=4.65

1 litre of gas at STP is expanded adibatically to 3 litre.Find work done by gas.gaama=1.4&3power1.4=4.65

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