Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

1 kg of ice at – 10°C is mixed with 4.4 kg of water at 30°C. The final temperature of mixture is: (specific heat of ice is 2100 J/kg/k) .

1 kg of ice at – 10°C is mixed with 4.4 kg of water at 30°C. The final temperature of mixture is: (specific heat of ice is 2100 J/kg/k) . 

Grade:

2 Answers

Arun
25763 Points
one year ago
Mass of ice, m = 1kg at -10°C 
mass of water, M = 4.4kg at 30°C 
heat flows through water to ice. so, heat gained by ice and heat lost by water. 
total heat gained by ice to melt = heat required by ice to reach the temperature 0°C + heat require to melt of ice 
= ms∆T + mL 
= 1 kg × 2100 J/Kg/°C × (0 -(-10)) + 1kg × 336000/Kg
= 21000 + 336000 
= 357000 J 
heat lost by water to reduce the temperature at 0°C = MS∆T'
= 4.4kg × 4200 × (30 - 0) = 554400> 357000 
so, temperature of mixture must be greater than zero. 
now, let's take, after melting ice reaches temperature A. 
then, heat is required to change temperature A is (554400 - 357000) = 197400J 
use formula, (m + M)S∆T = 197400 
or, (1 + 4.4)× 4200 × (A - 0) = 197400
A = 8.7°C
 
Vikas TU
14149 Points
one year ago
Dear student 
Check out this short method.
Given that,
Mass of ice = 1 kg
Temperature of ice = 283 K
Mass of water = 4.4 kg
Temperature of water = 303 K
Specific heat of ice = 2100 J/kg-K
We know that,
Specific heat of water = 4185.5 J/kg-K
Now, the final temperature of mixture is :
Tf = miTiCpi + mwTwCpw /(miCpi + mwCpw)
Put al the values 
Tf = 301k 
Hope this helps 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free