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When a rod of metal A is dipped in an aqueous solution of metal B (concentration of B2+ ion being 1 molar) at 25 degree Celsius), the standard electrode potentials are A2+/A= – 0.76 volts, B2+/B= +0.34 volts (a) A will gradually dissolve (b) B will deposit on A (ć) No reaction will occur (d) Water will decompose into H2 and O2.

When a rod of metal A is dipped in an aqueous solution of metal B (concentration of B2+ ion being 1 molar) at 25 degree Celsius), the standard electrode potentials are A2+/A= – 0.76 volts, B2+/B= +0.34 volts
(a)  A will gradually dissolve 
(b) B will deposit on A 
(ć) No reaction will occur 
(d) Water will decompose into H2  and O2.

Grade:12th pass

1 Answers

Arun
25750 Points
5 years ago
Reduction potential of B is more than A.
 
Hence reaction can't be happened.
 
Regards
Arun (askIITiams forum expert)

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