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        When a hydrocarbon is burnt completely the ratio of masses of CO2 and H2O formed is 44:27 the hydrocarbon is?
one year ago

Devang
52 Points
							let assume that   CxHY  is hydrocarbon         then                     CxHY   + ( x+y/4) O2  $\rightarrow$ x CO2  +  y/2 H2O1 mol of  CO2  give  44 gram of  CO2  thenx mol of  CO2  give  44x  gram of  CO2            = 44x  gm  …......(1) 1   mol   of   H2O give  18 gram  of  H2O   theny/2  mol  of  H2O  give  y/2(18)  gram  of  H2O = 9y  gm  ….......(2) we gave ratio of (1) & (2)  is 44:27then         44x / 9y = 44 / 27             x / y   = 1 / 3then hydrocarbon is  (CH3)n

one year ago
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• Test paper with Video Solution
• Mind Map
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