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Grade: 11
        
when 10^-8 moles of hcl is dissolved in one litre of water the ph of solution will be 
2 years ago

Answers : (1)

Arun
23506 Points
							
Dear student
 
when concentration of HCl becomes 10^-8 the concentration of [H+] of water ids 10^-7 and so cannot be neglected it should be taken into calculation
hence
[H+] in solution = concentration of HCL + concentration of [H] ion in water
= 10^-8 + 10^-7 
=1.1 * 10^-7
pH = -log[H+]
= -log[1.1*10^-7]=6.98.
 
Regards
Arun (askIITians forum expert)
2 years ago
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