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What would be the hydrogen ion concentration of 0.006M benzoic acid if Ka=6×10^-5 ?

Ayush , 7 Years ago
Grade 11
anser 1 Answers
RACH

Last Activity: 7 Years ago

 This is a basic question involving the formulae [H+]= (Ka*C)^1/2
It will be (Ka*C)^1/2 or,
(.006*6*10^-5)^1/2
or, 6*10^-4

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