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What weights of P4O6 and P4O10 will be produced by the combustion of 31g of P4 and 32g of oxygen leaving no P4 and O2

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one year ago

Arun
25333 Points
```							P4O6 = 56.3437% P P4O10 = 43.6420% P 31 g P = 31 / (31 + 32) = 49.2063% P So it becomes a problem in proportions: 100% P4O6 = 56.3437% z% P4O6 = 49.2063% 0% P4O6 = 43.6420% Find z. z / 100 = (49.2063 - 43.6420) / (56.3437 - 43.6420) Solve for z algebraically: z = 43.808% P4O6 By the Law of the Conservation of Matter, the total mass of P4O6 and P4O10 = 31g + 32g = 63g 43.808% of 63g = 27.6 g P4O6 63g - 27.6g = 35.4 g P4O10
```
one year ago
Khimraj
3007 Points
```							It is based on limiting reagenthere 2P4 + 8O2 gives P4O6+ P4O10so phosphorous having 31g and oxygen having 32gso P4 is the limiting reagentso ignoring oxygen 2P4----- gives P4O6so 2x124 gives 1220so 31 gives 152.5so the answer is 152.5
```
one year ago
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