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What weights of P4O6 and P4O10 will be produced by the combustion of 31g of P4 and 32g of oxygen leaving no P4 and O2

What weights of P4O6 and P4O10 will be produced by the combustion of 31g of P4 and 32g of oxygen leaving no P4 and O2

Grade:11

2 Answers

Arun
25750 Points
4 years ago
P4O6 = 56.3437% P 
P4O10 = 43.6420% P 
31 g P = 31 / (31 + 32) = 49.2063% P 
So it becomes a problem in proportions: 
100% P4O6 = 56.3437% 
z% P4O6 = 49.2063% 
0% P4O6 = 43.6420% 
Find z. 
z / 100 = (49.2063 - 43.6420) / (56.3437 - 43.6420) 
Solve for z algebraically: 
z = 43.808% P4O6 
By the Law of the Conservation of Matter, the total mass 
of P4O6 and P4O10 = 31g + 32g = 63g 
43.808% of 63g = 27.6 g P4O6 
63g - 27.6g = 35.4 g P4O10
 
 
Khimraj
3007 Points
4 years ago
It is based on limiting reagent
here 2P4 + 8O2 gives P4O6+ P4O10
so phosphorous having 31g and oxygen having 32g
so P4 is the limiting reagent
so ignoring oxygen 
2P4----- gives P4O6
so 2x124 gives 1220
so 31 gives 152.5
so the answer is 152.5

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