Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Grade: 11

                        

What is the solubility of Ag2CrO4 in water if the solubility product (KSP) = 1.3X10-11 (mol/L)3 ?

What is the solubility of Ag2CrO4 in water if the solubility product (KSP) = 1.3X10-11 (mol/L)3 ? 

one month ago

Answers : (1)

Vaijayanthi
13 Points
							
Ag2CrO4 dissociates as two moles of Ag+ and one mole of CrO4 2-.  One mole of the salt gives two moles of silver ions and 2 moles of chromate ions .  If s is the solubility of the salt, s moles of salt give 2s moles of Ag+ and s moles of CrO4 2-.  Hence the solubility product Ksp = [Ag+]^2  x [CrO4 2-] = (2s)^2 x s = 4s^3
4s^3 = 1.3 x 10 ^(-11)
s^3 = (1.3 x 10 ^ (-11))/4
s = cube root of above number
one month ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 141 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts
 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details