Question icon
Grade 11Mechanics

What is the no. Of wave of 6th orbit of hydrogen atom and find its radius

Profile image of Nitish  kumar
8 Years agoGrade 11
Answers icon

1 Answer

Profile image of Askiitians Tutor Team
ApprovedApproved Tutor Answer1 Year ago

To determine the number of waves in the sixth orbit of a hydrogen atom and to find its radius, we can use some fundamental principles from quantum mechanics and atomic theory. Let's break this down step by step.

Understanding the Hydrogen Atom's Orbits

In a hydrogen atom, electrons occupy specific energy levels or orbits, which are quantized. The principal quantum number, denoted as \( n \), indicates the energy level of the electron. For the sixth orbit, \( n = 6 \).

Calculating the Number of Waves

The number of wavelengths that fit into the orbit can be determined using the formula:

  • Number of wavelengths = \( n \)

Thus, for the sixth orbit, the number of wavelengths is simply:

  • Number of wavelengths = 6

This means that in the sixth orbit, there are six complete wavelengths of the electron's wave function fitting into the orbit.

Finding the Radius of the Sixth Orbit

The radius of an electron's orbit in a hydrogen atom can be calculated using the formula derived from Bohr's model:

  • Radius \( r_n = n^2 \cdot a_0 \)

Here, \( a_0 \) is the Bohr radius, which is approximately \( 0.529 \) angstroms (or \( 5.29 \times 10^{-11} \) meters). For the sixth orbit, where \( n = 6 \):

  • Radius \( r_6 = 6^2 \cdot a_0 = 36 \cdot 0.529 \, \text{Å} \approx 19.044 \, \text{Å} \)

To convert this into meters, we multiply by \( 10^{-10} \):

  • Radius \( r_6 \approx 19.044 \times 10^{-10} \, \text{m} = 1.9044 \times 10^{-9} \, \text{m} \)

Summary of Results

In summary, for the sixth orbit of a hydrogen atom:

  • The number of wavelengths is 6.
  • The radius of the sixth orbit is approximately \( 1.9044 \times 10^{-9} \) meters or \( 19.044 \) angstroms.

This understanding of atomic structure not only illustrates the quantized nature of electrons but also provides insight into the behavior of atoms in various states of energy. If you have any further questions or need clarification on any of these concepts, feel free to ask!