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What is the molar ratio of Fe2+ and Fe3+ in a mixture of FeSO4 and Fe2(SO4)3 having equal number of sulphate ions in both ferrous and ferric sulphate's?

What is the molar ratio of Fe2+ and Fe3+ in a mixture of FeSO4 and Fe2(SO4)3 having equal number of sulphate ions in both ferrous and ferric sulphate's? 

Grade:12

1 Answers

Arun
25750 Points
5 years ago
Given that equal number of sulphate ions in both FeSO4 and Fe2(SO4)3 FeSO4 Fe2(SO4)3No of moles of Fe (Fe2+) = 1 (Fe3+) = 2No of moles of Sulphate 1 3To make equal number of sulphate multiply column FeSO4 by 3 No of moles of Fe (Fe2+) = 3 (Fe3+) = 2 Thus the Fe2+ / Fe 3+ ratio are 3 : 2

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