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Molecular mass of KMnO
4
= 158 gmIn acidic medium, no. of electrons involved n is: MnO4-+ 8H++5e- ---> Mn+2 + 4H2O
So, equivalent mass = molar mass/ electrons involved= 158/ 5 = 31.6 gm/ equivalent
In strongly basic medium, MnO4- + 1e- ---> MnO42-
So, n = 1 , equivalent weight = 158/1 = 158gm/ qeuivalent
In neutral mediumMnO4- + 4H2O +3e- ---> MnO2 + 4OH-
Here, n = 3 so, equivalent weight = 158/3 = 52.66 gm/equivalent
Regards
Arun (askIITian forum expert)
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