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Grade: 11
Volume of co2 obtained at stp by the complete decomposition of 9.85 g na2co3 is.
4 years ago

Answers : (6)

Ashutosh Sharma
askIITians Faculty
181 Points

Na2CO3⇒ Na2O + CO2
1 mole of sodium carbonate give 1 mole of carbon dioxide.
as 105.98g sodium carbonate gives 44.01g carbon dioxide
therefore, 9.85 g sodium carbonate gives = 9.85 × 44.01 =4.09 g of CO2 105.98
Moles of CO2 mole = weight =4.09/44.01= 0.092 mole
Molar mass

1 mole of gas = 22.4 L gas
Therefore,0.092 mole of CO2 = 22.4 × 0.092 = 2.06 L CO2.

4 years ago
Rahul Ray
24 Points
On calculating this reaction one might get answer 2.08 litres but as Na2co3 is soda ash and it does not decomposes on heating even to redness
And co2 does not evolved
  So the answer will be zero litres
3 years ago
11 Points
							Na2co3 requires temperature above 500 degree Celsius to decompose that is not possible at STP so the answer will be zero cow evolved
2 years ago
SJ Nihal
13 Points
							Na2CO3 on decomposition gives CO2 .This is unfair if , 9.85 gm of sodium carbonate decompose and 2.08 litres CO2 formed as per calculation. As it does not decompose formally by heating .
2 years ago
Prabal Sarkar
13 Points
Na2CO3 require a high temperature(500℃).As the reaction happen in STP. So it can not get proper heat to make gasious CO2. So the volume of CO2 is Zero.....
one year ago
13 Points
It's answer will be zero bcz there will be no effect on Na2CO3 on decomposition
It need lots of energy to break the bonds ofNa2CO3 which is not possible in ordinary heating.
one year ago
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