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Volume occupied by molecules of one mole of a gas at NTP , each having a radius of 1Angstorm is
At NTP 1 mole of a gas occupies a volume of 22.4 litre.Also at NTP number of gas molecules in 1 mole of a gas is NA( Avogadro number 6.023×1023).So volume occupied by a single molecule is22.4/NA litre.
As the question says volume occupied by molecules of 1mole gas at NTP,it will simply be 22.4 lit.You do not have to calculate anything.
I found this ans.but how is it? Volume of 1 mole of molecules=N×(4v)(b=4v)=(6.02×10^23)(4×4/3 πr^3)=(6.02×10^23)(4×4/3× 22/7 )×(10^-8cm)^3=10.09 cm^3 or ml
Why are you multiplying by 4?The volume of a single molecule is (4/3)××r3If you multiply this with 6.023×1023 you will get almost 25 litre which is close to 22.4 litre,
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