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Grade: 12th pass
        
Vapour pressure of pure water is 40mm. If a non volatile solute is added to it vapour pressure falls by 4mm. Hence molality of solution is? 
one year ago

Answers : (1)

Khimraj
3008 Points
							
Relative lowering in vapour pressure
(Po – P)/P = 4/40 = 0.1 = xs
So xo = 0.9
m = 1000*xs/xo*Mo  =  1000*0.1/0.9*18 = 6.17 m
Hope it cleras....................
one year ago
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