Vapour pressure of pure water is 40mm. If a non volatile solute is added to it vapour pressure falls by 4mm. Hence molality of solution is?

Question

Khimraj · Answer

Relative lowering in vapour pressure (P o – P)/P o = 4/40 = 0.1 = x s So x o = 0.9 m = 1000*x s /x o *M o = 1000*0.1/0.9*18 = 6.17 m Hope it cleras....................

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Vapour pressure of pure water is 40mm. If a non volatile solute is added to it vapour pressure falls by 4mm. Hence molality of solution is?

Vapour pressure of pure water is 40mm. If a non volatile solute is added to it vapour pressure falls by 4mm. Hence molality of solution is?

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Vapour pressure of pure water is 40mm. If a non volatile solute is added to it vapour pressure falls by 4mm. Hence molality of solution is?

Vapour pressure of pure water is 40mm. If a non volatile solute is added to it vapour pressure falls by 4mm. Hence molality of solution is?

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