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UV light of wavelength 300 nm and intensity 1 W/m 2^ falls on a surface of a photoelectric material. If one percent of the incident photons produce photo electrons, then the no. of photo electrons emitted from an area of 1cm 2^ of surface is nearly
Dear student Number of photons falling on the surfac= (300*10^-9)/(6.63*3) *10^34 * 10^-8 = 1.50829 *10^18As only 1% of photo-electrons are liberated, so, only 1.50829×10^16 photons are ejected per second per m^2 So ,1 cm^2 = 1.50829 *10^16 *10^-4 photons of ejected per second. .
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