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upon mixing 1ooml of 0.1 M K2So4 &100ml of 0.05M Bacl2. BaSo4 forms .how many moie of BaSo4 are formed

upon mixing 1ooml of 0.1 M K2So4 &100ml of 0.05M Bacl2. BaSo4 forms .how many moie of BaSo4 are formed

Grade:11

1 Answers

Avinash
askIITians Faculty 1241 Points
8 years ago
K2SO4+BaCl2 → BaSO4 + 2KCl
Above equation represents 1 mole of Potassium sulphate reacts with 1 mole of Barium chloride to form 1 mole of Barium sulphate
For Potassium sulphate0.1 M = 0.1 mole/litre = 0.01 mole/100 ml
ForBarium chloride 0.05 M = 0.005 mole/100 ml

So0.01 mole of Potassium sulphate reacts with 0.005 mole of Barium chloride to form 0.005 mole of Barium sulphate
(0.005 moles ofPotassium sulphate left unreacted)


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