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Grade: 12th pass

                        

Uncertainty in the position of an electron (mass=9.1X10 -31 kg) moving with a velocity 300m/s accurate upto 0.001% will be:

2 years ago

Answers : (1)

aparazita sharma
41 Points
							
uncertainity in position can be easily calculated with the help of heisenberg’ uncertainity formula which is -
                                                    \Delta x.\Delta p= h/4\Pi
here \Delta x is change in position (which we have to calculate) and \Delta p is change in momentum which can be written as m\Delta v as m would be constant for electron.
as velocity is accurate upto 0.001 % so \Delta v can be calculated as 0.001 % of 300 or 1 * 300/ 105 which is equal to 
3*10-3  . Now putting value of m ,  \Delta v , h (6.6 * 10-34) and 4\Pi we can get uncertainity in position as
                                             \Delta x=6.6 * 10-34 / 4 * 3.14 *9.1 * 10-31 *3 *10-3           which is equal to 1.92*10-2 which is uncertainity in position.
 
PLEASE APPROVE MY ANSWER
2 years ago
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