0

Guest

Courses New

The vapour pressure of pure water is 760 mm at 25 degree Celsius the the vapour pressure of solution containing 1 m solution of glucose will be

The vapour pressure of pure water is 760 mm at 25 degree Celsius the the vapour pressure of solution containing 1 m solution of glucose will be

Grade:12

2 Answers

Arun
25750 Points
4 years ago
Dear student
 
Molality 1 m
 
1 * 10^-3 * 18 = 760 -p /760
 
p = 746.3w mm Hg
 
Hope it helps
 
Regards
Arun (askIITians forum expert)
SWAYAM PRAKASH MALIK
36 Points
2 years ago
According to the question ,
Molality = 1 m ,
Now , 760-p/p = 1 * 10^-3 * 18 ,
=> p = 746.3 mm Hg . 
Hope it helps.

Think You Can Provide A Better Answer ?

Other Related Questions on Physical Chemistry

View all Questions »

ASK QUESTION

Get your questions answered by the expert for free

Answer and earn gift vouchers

Win Gift vouchers upto Rs 500/-

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Click Here Know More

Complete Self Study Package designed by Industry Leading Experts

Click Here Know More

Live 1-1 coding classes to unleash the Creator in your Child

Click Here Know More

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Click Here Know More