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Grade: 11
        
  1. ​THE VAPOUR PRESSURE OF ACETONE AT 20 C IS 185 TORR. WHEN 1.2 G OF A NON – VOLATILE SUBSTANCE WAS DISSOLVED IN 100G OF ACETONE AT 20 C ITS VAPOUR PRESSURE WAS 183 TORR . THE MOLAR MASS OF THE SUBSTANCE IS
10 months ago

Answers : (1)

BIKRAM
53 Points
							
This question is related to lowering of vapour pressure. Roult’s law P = X1×P0; X1=(183/185)=0.9891 ;P0=185 torr ,P=183 torr
: amount of acetone= 100/58 = 1.724 mol;amount of substance =1.2/M;
X1=1.724/(1.724 +1.2/M)= 0.9891;
1.724 +1.2/M =1.7429 ; M = 1.2/(1.7429-1.724) = 63.5
10 months ago
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