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The vapour density of mixture containig NO2 and N2O4 is 27.6.The mole fraction of N2O4 is?

The vapour density of mixture containig NO2 and N2O4 is 27.6.The mole fraction of N2O4 is?

Grade:11

3 Answers

Arun
25750 Points
6 years ago
Dear student

Molar mass of the mixture = 27.6 x 2 = 55.2 g
Let x moles of N2o4 be present in the 100 mole mixture
So,(100-x) x 46 + 92x = 100 x 55.2
=> 100 - x + 2x = 5520/46 = 120
=> 100 + x = 120
=> x = 20
Hence,mole fraction of N2O4 in the mixture = 20/100 = 0.2
Regards
Arun (askIITians forum expert)
Vishal Kumar
29 Points
2 years ago
Degree of dissociation = D/d -1 = 46/27.6 -1 = 18.4/27.6
[N2O4] = 1- [18.4/27.6] = 1/3
Total mole = 1+ [18.4/27.6] = 46 / 27.6
Mole fraction of N2O4 = 1/3 × 27.6/46 = 0.2
Ujjawal Mishra
22 Points
2 years ago
 All  are telling anwer in very tough way. We cannot understand even a single step. Its waste of time for us.

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