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the value of observed and calculated molecullar wts of silver nitrate are92.64 and 170 respectively.The degree of dissociation would be

the value of observed and calculated molecullar wts of silver nitrate are92.64 and 170 respectively.The degree of dissociation would be

Grade:12

1 Answers

Karam singh
15 Points
5 years ago
i=calculated colligative property/observed colligative propertyi=170/92.64=1.835For AgNO3 (n)=2i=1+alpha(n-1)alpha(degree of dissociation)=i-1=1.835-1=0.835

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