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The time taken for a certai volume of a gas `X` to diffuse through a small hole in 2 minutes.It takes 5.65 minutes to diffuse under the similar conditions. The molecular weight of gas `X` is.
Rate of diffusion is given as = > kPA/(root(MT)) = dx/dtdx/2 = PA/root(MT)..................(1)dx/5.65 = PA/root(MT)The conditions are insufficient.There shoukd be changein any one thing like ppressure area or temp for 5.65 minutes.check the question.
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