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The ratio of 1st, 2nd , 3rd ionisation energies of lithium is 1:4:9. Find The energy in joules per mole for the reaction Li(g) - Li3+ + 3e
Reacns. for first second and third ionisation energies respectively are:Li ---------> Li+ + e- | 1JLi+ -----------> Li2+ + e- | 4JLi2+ -------------> Li3+ + e- | 9JAdding all three eqns. we get,Li ----------> Li3+ + 3e- | 1 + 4 + 9 => 14 Joules.Hence.
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