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The rate of two reaction are k1>k2.how are the activation energies of these reactions,e1and e2,related

Naqeeb Rocksz , 7 Years ago
Grade 12th pass
anser 1 Answers
poonam

Last Activity: 7 Years ago

K1/k2=(Ae^-e1/RT)/ (Ae^-e2/RT)>1Applying log on both sides(e2-e1)/RT >0 so e2>e1As log1 is 0 so e2will be greater than e1

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