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The rate constant for the decomposition of hydrocarbons is 2.418 × 10–5s–1 at 546 K. If the energy of activation is 179.9 kJ/mol, what will be the value of pre-exponential factor?

The rate constant for the decomposition of hydrocarbons is 2.418 × 10–5s–1 at 546 K. If the energy of activation is 179.9 kJ/mol, what will be the value of pre-exponential factor?

Grade:8

1 Answers

Sunil Kumar FP
askIITians Faculty 183 Points
8 years ago
value of pre-exponential factor-809_Wed Aug 20 15-05-24.jpg

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