MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
Menu
Grade: 12th pass
        
the previous question 
 
 
 
dddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd
one month ago

Answers : (2)

Saurabh Koranglekar
askIITians Faculty
3161 Points
							Dear student

What do you mean my previous question

Regards
one month ago
Vikas TU
8825 Points
							
P(π/4) = aCosπ/4 + bSinπ/4 
= (sqrt2 , 1 )-- Cordinate of P 
S coordinate is (sqrt 2  0 )
S' coordinate is (- sqrt 2 , 0) 
Equation of PS = x-sqrt2 = 0 
Equation of PS' = 2*sqrt2 y = x+ sqrt2 
Angle bisector 
(x - sqrt 2 )/ 1 = (+ or -) (x - 2sqrt2 +2 )/sqrt(1+8)
Solve this you will get 
x + sqrt2 y = 2*sqrt2 
A is correct ans. 
one month ago
Think You Can Provide A Better Answer ?
Answer & Earn Cool Goodies


Course Features

  • 731 Video Lectures
  • Revision Notes
  • Previous Year Papers
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Test paper with Video Solution


Course Features

  • 141 Video Lectures
  • Revision Notes
  • Test paper with Video Solution
  • Mind Map
  • Study Planner
  • NCERT Solutions
  • Discussion Forum
  • Previous Year Exam Questions


Ask Experts

Have any Question? Ask Experts

Post Question

 
 
Answer ‘n’ Earn
Attractive Gift
Vouchers
To Win!!! Click Here for details