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`        The pH of a solution by mixing 100 ml of 0.2M CH3COOH with 100 ml of 0.2M NaOH. pKa for CH3COOH = 4.74`
2 years ago

Vikas TU
7024 Points
```							               CH3COOH + H2O ----------> CH3COO-   +       H3O+At eqm.      0.2-x                                  x                       xfor x very very less 0.2 – x = 0.2Hence, x^2/0.2 = anitlog(Ka)x = 0.001908 approx.[H3O+] = 0.00198and OH- = > (0.02-0.00198)/2 = > 0.099 approx. Hence, pH = -log(1.01x10^-13) => 12.99 or 13.
```
2 years ago
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