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The ph of a mixture of 0.01m hcl and 0.1m ch3cooh os approximately?
0.01M Hcl and 0.1M CH3COOH is Given So H+ in HCl will be 10-2 and also in CH3COOH is 10-1 Let volume of HCl and CH3COOH be V According to formula H+ =N1V1 + N2V2/ total volume here N1=1* 10-2 and N2=1*10-1 so by putting in formula,H+= 10-2* V +10-1* V/2VH+=11*10-2/2H+= 5.5 * 10-2So, PH= - log[H+] Therefore PH= - log[5.5 * 10-2]PH=2- log 5.5PH=2-0.74 PH=1.26
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