Physical Chemistry> The orbital angular momentum of a p elec...

The orbital angular momentum of a p electron is given as.Explain?

Aadil Bashir , 7 Years ago

Grade 11

3 Answers

HIAMNSHU

Last Activity: 7 Years ago

Orbital angular momentum of an electron in particular orbital is given by under root l(l+1) h/2pi where `l` is azimuthal quantum no. For p orbital l=1 so orbital angular momentum is \/2 h/2pi. h/2pi comes from the wave nature consideration of electron. Waves associated with electrons so circumference of a circle must be integral multiple of wavelength. So only these orbits are permissible otherwise wave will intersect and amplitude become zero that means no possibility of electron to be found in that orbit.

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ananya

Last Activity: 7 Years ago

The formulae for finding out the orbital angular momentum is under roor l(l+1) × h/2pi , as we know that lfor p subshell =1 therefore keeping the values we get = under root 1(1+1)×h/2pi =underroot 2 × h/2pi or h/under root 2×pi. hope it will help.. :)

Rishi Sharma

Last Activity: 4 Years ago

Dear Student,
Please find below the solution to your problem.

Orbital angular momentum of an electron in particular orbital is given by under root l(l+1) h/2pi where `l` is azimuthal quantum no. For p orbital l=1 so orbital angular momentum is \/2 h/2pi. h/2pi comes from the wave nature consideration of electron. Waves associated with electrons so circumference of a circle must be integral multiple of wavelength. So only these orbits are permissible otherwise wave will intersect and amplitude become zero that means no possibility of electron to be found in that orbit.

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