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The number of moles of kmO4 that will be needed to react completely with one of ferrous oxalate in acidic solution is
KMnO4 + FeC2O4 + H ------> Mn2+ + Fe3+ + 2CO2KMnO4 = 5 electronsferrous oxalate in acidic solution = 3 electronswhile reaction exchange of electrons takes place..........so3 moles of KMnO4 = 5 moles of FeC2O45 moles of FeC2O4 = 3 moles of KMnO4so 1 mole of FeC2O4 = 3/5 moles of KMnO4hence 3/5 moles of KMnO4 will be needed to react completely with one mole of ferrous oxalate in acidic solution.....
KMnO4 + FeC2O4 + H ------> Mn2+ + Fe3+ + 2CO2
KMnO4 = 5 electrons
ferrous oxalate in acidic solution = 3 electrons
while reaction exchange of electrons takes place..........so
3 moles of KMnO4 = 5 moles of FeC2O4
5 moles of FeC2O4 = 3 moles of KMnO4
so 1 mole of FeC2O4 = 3/5 moles of KMnO4
hence 3/5 moles of KMnO4 will be needed to react completely with one mole of ferrous oxalate in acidic solution.....
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