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The number of moles of kmO4 that will be needed to react completely with one of ferrous oxalate in acidic solution is The number of moles of kmO4 that will be needed to react completely with one of ferrous oxalate in acidic solution is
KMnO4 + FeC2O4 + H ------> Mn2+ + Fe3+ + 2CO2KMnO4 = 5 electronsferrous oxalate in acidic solution = 3 electronswhile reaction exchange of electrons takes place..........so3 moles of KMnO4 = 5 moles of FeC2O45 moles of FeC2O4 = 3 moles of KMnO4so 1 mole of FeC2O4 = 3/5 moles of KMnO4hence 3/5 moles of KMnO4 will be needed to react completely with one mole of ferrous oxalate in acidic solution.....
KMnO4 + FeC2O4 + H ------> Mn2+ + Fe3+ + 2CO2
KMnO4 = 5 electrons
ferrous oxalate in acidic solution = 3 electrons
while reaction exchange of electrons takes place..........so
3 moles of KMnO4 = 5 moles of FeC2O4
5 moles of FeC2O4 = 3 moles of KMnO4
so 1 mole of FeC2O4 = 3/5 moles of KMnO4
hence 3/5 moles of KMnO4 will be needed to react completely with one mole of ferrous oxalate in acidic solution.....
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