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Grade: 12th pass
        
The number of free electrons per 10 mm of an ordinary copper wire is 2 x 1021. The average drift speed of the electrons is 0.25 mm/s. The current flowing is: A. 0.8 A B. 8 A C. 80 A D. 5 A
4 years ago

Answers : (1)

Vasantha Kumari
askIITians Faculty
38 Points
							

Solution:

Here, we are given that the number of free electrons = 2 x 10 21 and average drift speed is 0.25mm/s.

Thus, the passing strength thr the cross section in one second n = 2 x 10 21 / 10 x 0.25 = 5 x 1019

And I = charge per second = ne

= 5 x 1019 x 1.6 x 10–19

The average drift speed of current flowing = 8A

Thanks & Regards,

Vasantha Sivaraj,

askIITians faculty

4 years ago
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