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`        The normality of 4.9% (w/w) H2SO4 solution having density 1.02g/ml is`
one year ago

```							4.9 % acid by mass means 4.9g acid in 100 g solution.  Density = 1.02 g/mLVolume of  solution = Mass /density = 100/1.02 = 98.03 mlMolar mass sulphuric acid H₂So₄ = 2*1 + 32 + 4*16 = 98g/molNumber of moles of sulphuric acid = mass /  molar mass=4.9 / 98=0.05Molarity = number of moles / volume of solution in litres= 0.05 / 0.9803= 0.051 M Normality = Molarity * Basicity= 0.051*2 =0.102 NHence, the normality of 4.9% of H₂So₄ of density 1.02g/ml is 0.102N
```
one year ago
```							4.9% w/w H2SO4 means4.9g H2SO4 in 100ml solution find molaritym = (4.9 × 1000) / (98×100)m= 0.5then, find normality by multiplying molarity by valency factor.valency factor for H2SO4 is 2
```
one year ago
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