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The normality of 4.9% (w/w) H2SO4 solution having density 1.02g/ml is
one month ago

Answers : (2)

Arun
22331 Points
							
4.9 % acid by mass means 4.9g acid in 100 g solution. 
 Density = 1.02 g/mL
Volume of  solution = Mass /density
 = 100/1.02
 = 98.03 ml
Molar mass sulphuric acid H₂So₄ = 2*1 + 32 + 4*16 = 98g/mol
Number of moles of sulphuric acid = mass /  molar mass
=4.9 / 98
=0.05
Molarity = number of moles / volume of solution in litres
= 0.05 / 0.9803
= 0.051 M 
Normality = Molarity * Basicity
= 0.051*2 =0.102 N
Hence, the normality of 4.9% of H₂So₄ of density 1.02g/ml is 0.102N
 
 
one month ago
Vikas TU
8447 Points
							
4.9% w/w H2SO4 means
4.9g H2SO4 in 100ml solution 
find molarity
m = (4.9 × 1000) / (98×100)
m= 0.5
then, find normality by multiplying molarity by valency factor.
valency factor for H2SO4 is 2
one month ago
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