The normality of 4.9% (w/w) H2SO4 solution having density 1.02g/ml is
The normality of 4.9% (w/w) H2SO4 solution having density 1.02g/ml is
Suraj Kumar , 6 Years ago
Grade
Physical Chemistry> The normality of 4.9% (w/w) H2SO4 solutio...
5 Answers
Arun
Last Activity: 6 Years ago
4.9 % acid by mass means 4.9g acid in 100 g solution.
Density = 1.02 g/mL
Volume of solution = Mass /density
= 100/1.02
= 98.03 ml
Molar mass sulphuric acid H₂So₄ = 2*1 + 32 + 4*16 = 98g/mol
Number of moles of sulphuric acid = mass / molar mass
=4.9 / 98
=0.05
Molarity = number of moles / volume of solution in litres
= 0.05 / 0.9803
= 0.051 M
Normality = Molarity * Basicity
= 0.051*2 =0.102 N
Hence, the normality of 4.9% of H₂So₄ of density 1.02g/ml is 0.102N
Density = 1.02 g/mL
Volume of solution = Mass /density
= 100/1.02
= 98.03 ml
Molar mass sulphuric acid H₂So₄ = 2*1 + 32 + 4*16 = 98g/mol
Number of moles of sulphuric acid = mass / molar mass
=4.9 / 98
=0.05
Molarity = number of moles / volume of solution in litres
= 0.05 / 0.9803
= 0.051 M
Normality = Molarity * Basicity
= 0.051*2 =0.102 N
Hence, the normality of 4.9% of H₂So₄ of density 1.02g/ml is 0.102N
Vikas TU
Last Activity: 6 Years ago
4.9% w/w H2SO4 means
4.9g H2SO4 in 100ml solution
find molarity
m = (4.9 × 1000) / (98×100)
m= 0.5
then, find normality by multiplying molarity by valency factor.
valency factor for H2SO4 is 2
Nisha Sangwan
Last Activity: 4 Years ago
4.9 % acid by mass means 4.9g acid in 100 g solution.
Density = 1.02 g/mL
Volume of solution = Mass /density
= 100/1.02
= 98.03 ml
Molar mass sulphuric acid H₂So₄ = 2*1 + 32 + 4*16 = 98g/mol
Number of moles of sulphuric acid = mass / molar mass
=4.9 / 98
=0.05
Molarity = number of moles / volume of solution in litres
= 0.05 / 0.9803
= 0.051 M
Normality = Molarity * Basicity
= 0.051*2 =0.102 N
Hence, the normality of 4.9% of H₂So₄ of density 1.02g/ml is 0.102N
Aniket Raj
Last Activity: 4 Years ago
4.9 % acid by mass means 4.9g acid in 100 g solution.
Density = 1.02 g/mL
Volume of solution = Mass /density
= 100/1.02
= 98.03 ml
Molar mass sulphuric acid H₂So₄ = 2*1 + 32 + 4*16 = 98g/mol
Number of moles of sulphuric acid = mass / molar mass
=4.9 / 98
=0.05
Molarity = number of moles / volume of solution in litres
= 0.05 / 0.09803
= 0.51 M
Normality = Molarity * Basicity
= 0.51*2 =1.02 N
Hence, the normality of 4.9% of H₂So₄ of density 1.02g/ml is 1.02N
irshad hussain
Last Activity: 4 Years ago
Molarity={(w/w%)×10×(density in g/ml)}÷(Molar mass of solute in g)
M = (98*10*1.8)/98
= 18M
Normality = Molarity * nfactor(For H2SO4 2,Dibasic acid)
= 18*2
= 36N
Molality =(1000*Molarity)/{(1000*density in g/ml)-(Molar mass of solute in g*Molarity)}
=(1000*18)/(1000*1.8)-(98*18)
= 18000/36=500m
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