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The no.of moles of NaOH formed by the electrolysis of a sloution containing 0.585g of NaCl using platinum electrode is

The no.of moles of NaOH formed by the electrolysis of a sloution containing 0.585g of NaCl using platinum electrode is 
 
 

Grade:12

1 Answers

Vikas TU
14149 Points
5 years ago
From the mole concept -2 and the electrolysis law of electrodes:
number of moles x valence factor =  constant.
Therfore,
n x 1 = (0.585/58.44)*1
n = 0.01001 moles.

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