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The no.of hydronium ions present in 10ml of water at 25 centigrade ?

shreya , 12 Years ago
Grade 12
anser 1 Answers
reshma lr
pH=7 7=-log[H+] con of H+=10^-7 n=cv =10^-7*10*10^-3 =10^-9moles no of ions=6.o22*10^23*2*10^-9 =12.044*10^14 hope this helped you
Last Activity: 12 Years ago
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